Calculate $H$ for the reaction: $C_2{H}_4(g)+H_2(g)C_2{H}_6(g),$ from the following data.

$C_2{H}_{4(g)}+3O_{2(g)}2C{O}_{2(g)}+2H_2{O}_{(l)}$

$C_2{H}_{6(g)}+3\frac{1}{2}{O}_{2(g)}2C{O}_{2(g)}+3H_{2}O$

$H_{2(g)}+\frac{1}{2}{O}_{2(g)}{H}_2{O}_{(l)}$

$(1)$

$H=-1411.kJ$

$H=-1560.kJ$

$H=-285\mathrm{.}8kJ$