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Calculate H(kk/mol) for the following reaction: 2Fe(s)+23O2(g)Fe2O3(s) Giventhefollowing:2Fe(s)+6H2O(l)2Fe(OH)3(s)+3H2(g);Fe2O3(s)+3H2O(l)2Fe(OH)3(s);2H2(B)+O2(g)2H2O();H=+322molkJH=+289molkJH=572molkJ
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