Calculate $pH$ and $H^{+}$of $0\mathrm{.}02$ mole of $Ba(OH{)}_2$ dissolved in $0\mathrm{.}5L$ water?

$12\mathrm{.}60$ and $1\mathrm{.}25{10}^{-13},$ respectively.

$12\mathrm{.}90$ and $1\mathrm{.}25{10}^{-11},$ respectively.

$12\mathrm{.}90$ and $1\mathrm{.}25{10}^{-13},$ respectively:

$12\mathrm{.}60$ and $2\mathrm{.}5{10}^{-13}$ respectively.