calculate T for the water using T = |Tf-Ti|. show your work fir one trial

Lab 1. A Report - Sugar Data Table Mass of sample (9) Initial temperature (C) Final temperature (C) Trial 1 1. 0152 25.00 26.694 Trial 2 1.041.37 25.000 2b.pl Analysis 1. Write a complete balanced chemical equation for the combustion of sucrose, G.2H2011). 2. Calculate AT for the water using AT = 1T-T). Show your work for one trial. Trial 1 Trial 2 3. Calculate the moles (n) of sucrose in the sample. Show your work for the first trial only. (MWerne = 342.3 g/mol). All numbers must have units. Trial 1 - Trial 2 4. Recalling that, Cout+qin = 0, AH comb - (Ciste AT) for sucrose. Report your answer in kl/mol. Note that Cystem = 10.310 kJ/K. Show your work for the first trial only. Trial 1 Trial 2 5. If the accepted value for the heat of combustion for sugar is 5639 kJ/mol, calculate the percent error. Remember, the best accepted value is always an average of multiple trials! Show your work. |data - accepted value|| % error = x100 accepted value % error Lab 1. B Report - Chicken Fat Data Table Trial 1 Trial 2 Mass of sample (9) 0.9029 0.9163 Initial temperature (C) 25. 003 25.000 Final temperature (C) 20.297 31.628 Analysis 6. Calculate at for the water using AT = 1T-T. Show your work for one trial Trial 1 Trial 2 7. Calculate the moles of chicken fat (MW = 797.7 g/mol) in the sample. Show your work for the first trial only. Trial 1 Trial 2 8. Calculate the Acomo for chicken fat. Note that Cear = 10.310 kJ/K. Show your work for the first trial only Trial 1 Trial 2 - 9. If the accepted value for the heat of combustion for chicken fat is 30,038 kJ/mol, calculate the percent error. Remember, the best accepted value is always an average of multiple trials! Show your work Idata - accepted valuel 2100 % error = accepted value % error Lab 1. C Report - TNT Data Table Trial 1 Mass of sample (9) 0.938 Initial temperature (C) 25.002 Final temperature (C) 260.360 Analysis 10. Calculate AT for the water. Show your work for one trial. Trial 2 0.9104 26.365 27.756 Trial 1 Trial 2 = 11. Calculate the moles of TNT (GM:N 02) in the sample. Show your work for the first trial only. IMWTNT = 227.13 g/moll Trial 1 = Trial 2 12. Calculate the como for TNT. Note that Ccat = 10.310 kJ/K. Show your work for the first trial only. Trial 1 Trial 2 13. If the accepted value for the heat of combustion for TNT is 3406 kJ/mol, calculate the percent error. Remember, the best accepted value is always an average of multiple trials! Show your work. data - accepted value %6 error *100 accepted value %error =