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Calculate the average H 0 rxn from the two runs. [NaOH] / mol L -1 : 0.9996 [HCl] / mol L -1 : 1.0011 HCl(aq)
Calculate the average H0rxn from the two runs.
[NaOH] / mol L-1: 0.9996
[HCl] / mol L-1: 1.0011
HCl(aq) + NaOH(aq) ---> NaCl(aq) + H2O(l)
run #1. final mass= 104.76g. T=6.00K. qcontents= -2543.54J
Run #2. final mass= 98.29g. T= 6.40K. qcontents=-2631.97J
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