Calculate the enthalpy for the reaction 2Fe(s) + 3/2O2(g) -> Fe2O3(s) from the following:

2FeO(s) +1/2O2(g) -> Fe2O3(s)

H= -280 kJ

2Fe(s) + O2(g) -> 2FeO(s)

H= -544 kJ

Express your answer as an integer and include the apprpriate units. Include a negative sign if the answer is negative but not if the answer is positive.