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Calculate the maximum numbers of moles and grams of H 2 S that can form when 147.3 g of aluminum sulfide reacts with 143.0 g


 
Calculate the maximum numbers of moles and grams of H2S that can form when 147.3 g of aluminum sulfide reacts with 143.0 g of water:
 
Al2S3 + H2O → Al(OH)3 + H2S [unbalanced]

 mol H2S
 
 g H2S
 
What mass of the excess reactant remains?
 
 g excess reactant

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