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Calculus Based Physics 2 (11%) Problem 8: A voltage source creates an electric current in a circuit. At one point in the current path, the
Calculus Based Physics 2
(11%) Problem 8: A voltage source creates an electric current in a circuit. At one point in the current path, the thin conducting wire is replaced with a wide but thin ribbon of conducting material which is located in the plane of the page. The region surrounding the wide conducting ribbon contains a uniform magnetic field perpendicular to the plane of the page, as shown.\f11% Part (d) A voltmeter is used to measure the potential difference between opposite sides of the conducting strip. Which of the following statements is correct for positive charge carriers? Grade Summary The potential drops moving from the left to the right edge due to the magnetic force on the charge carriers, and the potential increases Deductions 0% moving in the direction from the top towards the bottom of the page due to Ohm's Law. Potential 100% The potential increases moving from the left to the right edge due to Ohm's Law, and the potential decreases moving in the direction from Submissions the top towards the bottom of the page due to the magnetic force on the charge carriers. Attempts remaining: 4 The potential drops moving from the left to the right edge due to Ohm's Law, and the potential increases moving in the direction from the (25% per attempt) detailed view top towards the bottom of the page due to the magnetic force on the charge carriers. The potential is constant moving from the left to the right edge, and the potential increases moving in the direction from the top towards the bottom of the page due to the magnetic force on the charge carriers. The electric potential is constant over the whole conducting ribbon because the effects of the magnetic force and Ohm's Law cancel. Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback.11% Part (h) A voltmeter is used to measure the potential difference between opposite sides of the conducting strip. Which of the following statements is correct for negative charge carriers? The potential drops moving from the left to the right edge due to the magnetic force on the charge carriers, and the potential decreases Grade Summary Deductions 0% moving in the direction from the top towards the bottom of the page due to Ohm's Law. Potential 100% The potential increases moving from the left to the right edge due to Ohm's Law, and the potential also increases moving in the direction Submissions from the bottom towards the top of the page due to the magnetic force on the charge carriers. Attempts remaining: 4 The potential drops moving from the left to the right edge due to Ohm's Law, and the potential decreases moving in the direction from the (25% per attempt) detailed view top towards the bottom of the page due to the magnetic force on the charge carriers. The potential is constant moving from the left to the right edge, and the potential decreases moving in the direction from the bottom towards the top of the page due to the magnetic force on the charge carriers. The electric potential is constant over the whole conducting ribbon because the effects of the magnetic force and Ohm's Law cancel. Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback.11% Part (i) This effect where a magnetic field which is perpendicular to the direction of a current produces a potential difference in the direction perpendicular to both is known as the Hall Effect. In the actual experiment as set-up in the problem statement, we would see that the potential drops as we move from the upper edge of the strip towards the bottom of the page. From this observation we may conclude that Grade Summary O the carriers of electric current are electrons. Deductions 0% O the carriers of electric current are positively charged. Potential 100% O the carriers of electric current are negatively charged. Submissions O the carriers of electric current are protons. Attempts remaining: 4 (25% per attempt) O despite being a fascinating application of the Lorentz force, nothing new may be learned. detailed view Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedbackStep by Step Solution
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