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Can anyone help me with this question about bounding summation? Without using calculus (as in the previous exercise), show that, if n is a power
Can anyone help me with this question about bounding summation?
Without using calculus (as in the previous exercise), show that, if n is a power of 2 greater than 1, then, for H_n, the nth harmonic number, H_n lessthanorequalto 1 + H_n/2 Use this fact to conclude that H_n lessthanorequalto 1 + [log_2 n], for any n greaterthanorequalto 1Step by Step Solution
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