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Can anyone help. Thank you 2. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET8 5.5.044.MI. Evaluate the indefinite integral. (Use C for the constant of integration. )

Can anyone help. Thank you

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2. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET8 5.5.044.MI. Evaluate the indefinite integral. (Use C for the constant of integration. ) 4 3 dx 1+x8 2 tan -1(x2) + C x Need Help? Master It Submit Answer5. [-/1 Points] DETAILS SCALCET8 5.5.025.MI. Evaluate the indefinite integral. (Use C for the constant of integration.) 41 + ex dx Need Help? Watch It Master It Submit Answer12. [-/1 Points] DETAILS SCALCET8 5.4.033. Evaluate the integral. 8 X 2 dx X Need Help? Watch It Submit Answer\f16. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET8 5.4.005. Find the general indefinite integral. (Use C for the constant of integration.) (x1.9 + 9x 3.5) dx 0.34482758 2.9 + 9 4.5 + C 4.5 X Need Help? Watch It Submit AnswerTutorial Exercise Evaluate the indefinite integral. ( In(x)) 32 dx X Step 1 We must decide what to choose for u. If u = f(x), then du = f'(x) dx, and so it is helpful to look for some expression in In(x))37 ax = (In(x))37(_) dx for which the derivative is also present, though perhaps missing a x constant factor. For example, In(x) is part of this integral, and the derivative of In(x) is - which is also present. Step 2 If we choose u = In(x), then du = _ dx. If u = In(x) is substituted into x In(x))3 dx, then we have ( Jim( x)37 ax = /437 ( + dx). We must also convert - dx into an expression involving u, but we know already that _ dx = 1 1 du. Step 3 Now, if u = In(x), then x [ In ( x ) 37 ax = 4 37 du . 437 du = 38 In x 38 + C x 38 This evaluates as Enter your answer in terms of u. + C. Step 4 Since u = In(x), then converting back to an expression in x we get In x 38 1 38 + C= . dx X X Remember to use capital C.. Submit Skip (you cannot come back) Submit

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