Can I get assistance with the following. Here are the requirements

Modify the program Figure 2.10 (limit/num). Review the book section on the switch statement and the 'else if' clause Add new 'const' variables: base2, base3, base8, base10 and base16. Assign them the value the name implies Ask the user to enter a number base (2, 3, 8, 10 or 16) Follow the table below to output the correct value: base output ----- ------ 2 Binary 0..1 3 Trinary 0..2 8 Octal 0..7 10 Decimal 0..9 16 Hexidecimal 0..F In other words, the program used to do this: 99 low Now it should do this 8 Octal 0..7 If you run it again: 2 Binary 0..1 If you run it again: 16 Hexidecimal 0..F Use 'else if' statements AND the 'const' variables to test the input. Use an 'else' at the very end and print an error messge when the input is NOT 2,3,8,10 or 16 

Here is my code.

#include #include

int main(int argc, char** argv) { const int limit = 100; int num; scanf("%d", &num); if(num >= limit){ printf("high "); } else{ printf("low "); }

return (0); }

Thank you