Can I have some help?

The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to nd how the current I is changing (in A/s) at the moment when R = 361 Q, I = 0.07 A, % = 0.08 V/s, and $ = 0.05 0/5. (Round your answer to six decimal places.) A/s