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can I please get help on 1, 3, 4, 5, 6, 9, 10, 11, 15, 16, and 17 please I will rate up. Question 1

can I please get help on 1, 3, 4, 5, 6, 9, 10, 11, 15, 16, and 17 please I will rate up.

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Question 1 Question 3 part 1 of 1 10 points part 1 of 1 10 points Consider the case in which light ray A is A coin is at the bottom of a beaker. incident on mirror 1, as shown in the figure. The beaker is filled with 5.3 cm of wa- The reflected ray is incident on mirror 2 and ter (n1 = 1.33) covered by 2.2 cm of subsequently reflected as ray B. Let the an- liquid (n2 = 1.4) floating on the water. gle of incidence (with respect to the normal) on mirror 1 be 0A - 59% and the point of incidence be located 20 cm from the edge of contact between the two mirrors. mirror 2 BY Question 15 How deep does the coin appear to be from part 1 of 1 10 points 90 the upper surface of the liquid (near the top of the beaker)? A converging lens of focal length 0.156 m mirror 1 Answer in units of cm. forms a virtual image of an object. The image appears to be 0.86 m from the lens on the What is the angle of the reflection of ray B same side as the object. (with respect to the normal) on mirror 2? Question 4 What is the distance between the object Answer in units of . part 1 of 1 10 points and the lens? In the figure, a ray of light enters the liquid Answer in units of m. Question 5 part 1 of 1 10 points from air and is bent toward the normal as shown. Question 16 A narrow beam of light passes through a part 1 of 1 10 points plate of glass with thickness 2.84 cm and a refractive index 1.5. The beam enters from A convex lens is needed to produce an image 6.2 air at an angle 33.20. The goal is to calculate located 29 cm behind the lens that is 3.4 the the deviation d of the ray as indicated in the size of the object. figure. What focal length should be specified? Answer in units of cm. 33.2 10 Question 17 part 1 of 1 10 points 2.84 cm n - 1.5 A diverging lens is used to form a virtual 6.2 image of an object. The object is 86.7 cm in front of the lens, and the image is 41.8 cm in front of the lens. What is the index of refraction n for the Find the focal length of the lens. Find deviation d. liquid? Answer in units of cm. Answer in units of cm. Question 12 part 1 of 1 10 points An object is placed 20.3 cm in front of a convex mirror of focal length 10 cm. Note: Do convex mirrors have a positive or negative focal length? Consequently, the image will be 1. real, erect, bigger than object. 2. virtual, erect, bigger than object. 3. real, same size as object. 1. virtual, inverted, bigger than object. Question 9 part 1 of 1 10 points 5. real, inverted, bigger than object. 6. virtual, inverted, smaller than object. A concave mirror has a focal length of 10 cm. 7. real, erect, smaller than object. What is the position of the object if the 8. virtual, same size as object. image is erect and is 2 times larger than the 9. virtual, erect, smaller than object. object? Question 13 Answer in units of cm. Question 6 part 1 of 1 10 points Question 10 part 1 of 1 10 points Consider a prism, with index of refraction n = 1.81, that is immersed in a fluid. Light A concave makeup mirror is designed so srikes the surface of the prism as shown in the figure. that a person 32 cm in front of it sees an upright image magnified by a factor of 4. What is the radius of curvature of the mir- ror? Answer in units of m. Question 11 part 1 of 1 10 points A convex spherical mirror forms a virtual If the prism is surrounded by a fluid, what is image 0.56 times the size of the object. The the maximum index of refraction of the fluid object distance is 8.3 cm . that will still cause total internal reflection within the prism

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