Can I please get help with this C program. This is the requirements. If in the requirements it mentions C++ please provide answer in C as that is how I've written the code.

Modify the program Figure 2.10 (limit/num). Review the book section on the switch statement and the 'else if' clause Add new 'const' variables: base2, base3, base8, base10 and base16. Assign them the value the name implies Ask the user to enter a number base (2, 3, 8, 10 or 16) Follow the table below to output the correct values: base output ----- ------ 2 The first 4 powers of 2 3 The first 4 powers of 3 8 The first 4 powers of 8 10 The first 4 powers of 10 16 The first 4 powers of 16 Here is the kicker, DO NOT HARD CODE THE OUTPUT Duh..... We all know how to do this for 2: cout << " 1 2 4 8 " << endl; Instead use the proper const variable to calculate the power: cout << base2/base2 << " " << ... // you finish the calculations In other words, the program used to do this: 2 Binary 0..1 Now it should do this 2 1 2 4 8 If you run it again: 8 1 8 64 .... If you run it again: 16 1 16 .... Use 'else if' statements AND the 'const' variables to test the input. Use an 'else' at the very end and print an error messge when the input is NOT 2,3,8,10 or 16 AGAIN, DO NOT HARDCODE the values you print, calculate them 

My Code:

#include  #include  int main() { const int limit = 100; const int base2 = 2; const int base3 = 3; const int base8 = 8; const int base10 = 10; const int base16 = 16; int num; printf("Enter the value of the base 2, 3, 8, 10, or 16: "); scanf("%d", &num); if (num == base2) { printf("Binary 0..1"); } else if (num == base3) { printf("Trinary 0..2"); } else if (num == base8) { printf("Octal 0..7"); } // checking if it is base10 i.e 10 else if (num == base10) { printf("Decimal 0..9"); } else if (num == base16) { printf("Hexidecimal 0..F"); } else { printf("Invalid Input"); } return (0); }