can some body tell me what is wrong with my first assert statement in my code below. It always shows failed when executed. I am just tired. I exactly want why it is failing. I am using gcc.

#include #include #include #include #include #include #include #include

int main(int argc, char** argv) { if(argc != 2) { assert(fprintf(stderr, "Incorrect number of arguments. ") == -1); } char * end; errno = 0; //long n = strtol(argv[1], &end, 10); long n = strtol(argv[1], &end, 10);

//Ensure proper argument is passed.(To check that argument works and is passed without error) if (argv[1] == end) printf (" number : %lu invalid (no digits found, 0 returned) ", n); else if (errno == ERANGE && n == LONG_MIN) printf (" number : %lu invalid (underflow occurred) ", n); else if (errno == ERANGE && n == LONG_MAX) printf (" number : %lu invalid (overflow occurred) ", n); else if (errno == EINVAL) /* not in all c99 implementations - gcc OK */ printf (" number : %lu invalid (base contains unsupported value) ", n); else if (errno != 0 && n == 0) printf (" number : %lu invalid (unspecified error occurred) ", n); else if (errno == 0 && argv[1] && *end != 0) printf (" number : %lu valid (but additional characters remain) ", n);

for(int i = 1; i <= n; i++) { assert(printf("Process: %i %i ", getpid(), i) >= 0); } //return 0; exit(n); }