Can someone double check my work and verify that the Pearson Coefficient is .06

5. Check the following data for normality (Use the Pearson Coefficient (PC) equation): PC - 3(X - median) S 1236 3 20 34 44 47 52 67 70 72 ) 82 89 90 91 105 112 123 135 = 17 = 72.7 201= 72.7 32 + 20 2 + 34 2 +4 42+ 472+522+ 672+ 702+ 72 2+822+892+902+912+1052X mol = 72 + 1122+ 1232+ 1352 5= 34.31 17 ( 1 10 9 36 6 ) - (1236 ) 2 = 110936 PC = .06 52 = 17 ( 17-1) 17 ( 16 ) 358216 272 52=$1 316. 97. . PC = 3( 72.7-72) 72.1 34. 3 5= 36.3 34 . 3 =.06