can someone please help me solve my problem in a similar way i'm coding.

this is the 2nd time i'm posting this because the last answer made no sense to me

this is what the last person said and when i ran it it was incorrect i dont know what "lt" is please solve mine in a similar way to as i typed my program i'm still learning and am not an expert i don't know any other way other than the way i've been taught please keep it simple and help me. !!!

Write a program that asks the user for a positive integer value between 2 and 100 inclusively. The program should use a while loop to compute the sum of all integers from 1 up to the number entered. For example, if the user enters 50 , the loop will find the sum of 1,2,3,4, 50 and after the loop terminates, output the message, "Sum of numbers 1+2++50 is 1275 ". If the user enters an integer less than 2 or an integer greater than 100, the program should give the error message, "Invalid entry. Integer should be between 2 and 100. " and then terminate. Hint: You will need a counter and an accumulator. If needed, reference slide 2 of Lect5a_Part2_while_cont.pptx. Create a limit variable, take the input from user and populate it, and then use it in the while loop in place of 10. When the input as is shown in Figures 1&3, your program should produce the output as shown in Figures 2&4. Figure 1: (sample input) 50 Figure 2: (sample output, your output should actually include the ++ and not the actual numbers) Sum of numbers 1+2++50 is 1275 Figure 3: (sample input) 2 Figure 4: (sample output) 345678910111213141516171819202122232425262728//Lab28#includeusingnamespacestd;intmain(){//definevariablesintsum,num;//defineaccumulatorvariableandinitializeitto0intsum=0//definealimitvariabletobeinputbutusercin>>num;//readinthelimit//validatethelimitisbetween2and100inclusivelyif0return0; The code you have posted is incomplete. You need to define the variable n and assigr it a value. You also need to set the initial value of i to 0. \#include \ using namespace std; int main() \{ int i=0; int n; // define n int limit; int sum =0; cout \\> limit; n= limit; // assign a value to n for (i =0; i \ This code will find the sum of all numbers from 1 to the limit provided by the user. It starts the loop with i code > set to 0 and stops when i code > is greater than or equal to the limit entered by the user. It then prints out the sum of all the numbers