Can someone please help me with this project. Exact code (picture) is preferred for easy translation and practice.

Pay close attention to the return value for each function, as per the project specification. Programming style is important! Remember to Use whitespace between operators and operands Use descriptive variable names Add appropriate comments.

(1) Rock, Paper, Scissors

Start with the Rock, Paper, Scissors program that we talked about in class on week 6 (see posted class notes for week 6). Add a docstring, then add code to ask a player whether they would like to play the game (use Python input function), and execute the game code, or not, based on the answer. Finally, add code to allow players to play repeatedly (that is, at the end of each game, ask whether they would like to play again and execute the game code, or not, based on the answer).

(2) Include at least three additional test cases for the following count_vowels, find_min_max, and my_average functions

Note: Where examples for testing are needed, be sure to include input, and boundary input, e.g., 0, 1, empty strings, etc. (I will elaborate on this topic on Monday).

(2a) The following function is broken. The docstring describes what it is supposed to do.

def count_vowels(s):

'''

(str) -> int

Return number of vowels in s.

>>> count_vowels('The quick brown fox')

5

''' vowels = 'aeiou'

ctr = 0

for ch in s:

if ch in vowels:

counter += 1

return ctr

Fix the bug(s) in the current version of count_vowels. Comment any code you change. Generate a series of examples to test count_vowels

(2b) The following function is broken. The docstring describes what it is supposed to do.

def find_min_max(values):

''' (string) -> None

Find the maximum and minimum values in a non-empty string of digits and print them.

None value is returned.

>>> find_min_max('45312')

The minimum value is 1.

The maximum value is 5.

>>> find_min_max('428')

The minimum value is 2.

The maximum value is 8.

'''

mmin = 0

mmax = 0

for value in values:

if value > mmax:

mmax = value

if value < mmin:

mmin = value

print('The minimum value is', mmin)

print('The maximum value is', mmax)

#or

#print('The minimum value is {}'.format(mmin))

#print('The maximum value is {}'.format(mmax))

return None

Fix the bug(s) in the current version of find_min_max. Comment any code you change. Generate a series of examples to test find_min_max.

(2c) Suppose you have a data set of customer satisfaction survey results, with product ratings from 1 (poor quality) to 9 (high quality). Zeros indicate no answer. Here is a function that computes and returns the average product rating from the data set, a function parameter of type string. Zeros do not count toward the average. For no usable data, return 0.

The following function is broken. The docstring describes what it is supposed to do.

def my_average(dataset):

'''

(string) -> float

returns average of values in input string values, but zeros do not count at all

>>> my_average('23')

2.5

>>> my_average('203')

2.5

'''

count = 0

total = 0

for value in dataset:

if value != '0':

total += int(value)

count += 1

avg = total / count

return avg

Fix the bug(s) in the current version of my_average. Comment any code you change. Generate a series of examples to test my_average.

(3) As Time Goes By with bugs Oh, no someone started trying to improve working code without making a copy of the working version first. Now function minutesToYears is not returning the correct result. Find and fix the bugs in minutesToYears and/or its auxiliary functions. The revised functions should work for all of the examples given in the docstrings.

Comment any changes you make in the code.

def minutesToHours(minutes):

'''

(number) -> float

convert input minutes to hours;

return hours

>>> minutesToHours(60)

1.0

>>> minutesToHours(90)

1.5

>>> minutesToHours(0)

0.0

'''

hours = minutes / 60

hours = round(hours, 2)

print(hours)

return None

def hoursToDays(hours):

'''

(number) -> float

convert input hours to days; return days

>>> hoursToDays(24)

1.0

>>> hoursToDays(100)

4.17

>>> hoursToDays(0)

0.0

'''

days = hours / 24

return days

def daysToYears(days):

'''

(number) -> float

convert input days to years; return years

>>> daysToYears(365)

1.0

>>> daysToYears(100)

0.27

>>> daysToYears(0)

0.0

'''

days = 365

years = days / 365

years = round(years, 2)

return years

def minutesToYears(m):

'''

(int) -> float

input number m minutes is converted to equivalent number of years. return years. call auxiliary functions to do each step.

>>> minutesToYears(525600)

1.0

>>> minutesToYears(5256000)

10.0

>>> minutesToYears(394200)

0.75

>>> minutesToYears(0)

0.0

'''

minutesToHours(m)

hoursToDays(h)

daysToYears(d)

return y