Can you explain clearly how to get the final answer by showing all steps?

Decimal Bytes 4,096 2 Powers Decimal Bytes Mem. Unit 2 Powers 2 1 1B 212 2 2 213 2 4 214 2 8 215 2 16 216 2 32 217 26 64 218 2 128 219 2 256 220 2 512 221 220 1024 1KB 222 211 2,048 2KB 221 *Note that page numbering starts from 0. 8,192 16,384 32,768 65,536 131,072 262,144 524,288 1,048,576 2,097,152 4,194,304 8,388,608 Mem. Unit 2 Powers 4KB 24 8KB 25 16KB 226 32KB 27 64KB 228 128KB 229 256KB 250 512KB 231 IMB=10242 212 2MB 233 4MB 2 8MB 2 Decimal Bytes Mem. Unit 16,777,216 16MB 33,554,432 32MB 67,108,864 64MB 134,217,728 128MB 268,435,456 256MB 536,870,912 512MB 1,073,741,824 1GB=1024 2,147,483,648 2GB 4,294,967,296 4GB 8,589,934,592 8GB 17,179,869,184 16GB 34,359,738,368 32GB Consider a system having a physical memory of size S GB with frame size F KB. If page K is mapped to frame K+M, what is the physical address of the valid linear logical address A? S F M M LA 16 4 6000 1129655