can you help me solve the following questions

Earth's magnetic field is approximately 1/2 gauss, that is 50 micro-tesla because the SI field unit of a tesla is 10,000 gauss. Earth's north geographic pole is close to its south magnetic pole, and magnetic field is directed from the north to the south poles of a magnetic dipole so it goes from Earth's south geographic pole towards its north. Suppose you have wire carrying a large DC current from the south wall of a building to its north wall and that it is horizontal, on the floor. If Earth's field is parallel to the ground and does not dip, what force if any would the wire experience? O A downward force pushing onto the floor O A sideways force pushing it east O An upward force lifting it off the floor O No force because the wire and the field are parallelA solenoid is a series of loops of wire, one after another, to make a long tube. Along solenoid wound with fine wire carrying a current would generate a nearly uniform magnetic field inside the solenoid, and these devices are widely used for that purpose. They are also a basis of relays and actuators that can create mechanical motion from the interaction of this field with a material. You'll find a simple formula for the field inside a solenoid on the class website where it is derived from Ampere's law. Suppose we want to create a field inside the solenoid that is the same as Earth's magnetic field, typically arouns 50*10" T or 50 micro-tesla. We might do this to cancel Earth's field in a sensitive experiment for example. We build a solenoid with fine wire wrapped on a tube, and there are 1000 turns per meter of this wire. That is each loop of wire takes 1 mm along the coil. We connect the ends of the wire to a voltage source we can control such that current flows through the wire. Which of these is closest to the current you calculate that would create a magnetic field equal to Earth's field inside the solenoid? O less than a microampere O 40 microamperes O 40 milliamperes O more than 100 amperes O 40 amperesMatch the following physics concept with the math expression that describes it. The symbols are the usual ones, and are on our class website. These equations are basic ones uses to find magnetic fields and their effects. Power dissipated in a resistor A. Q/V v Capacitance B. 2k 1/R m Magnetic field around a long straight wire C. qv X B Field inside a solenoid v Force on a moving charge D. 12R v Voltage in a current loop and a changing field E. BIL Energy per time carried by a current across a voltage F. 4xk nl m v Force on a wire in a field G. VI H. - A (BA) / At10 points Save Answer Suppose that a single long wire carried a current of 100 A. This is several times the current required for a clothes dryer at home. At a distance of 2 cm from the wire, what would be its magnetic field? A tesla (T) is the SI unit of magnetic field. Reminder: When using formulas in physics, such as the one for the field around a wire carrying current, all quantities must be in "SI" units. That is, distance in meters, time in seconds, mass in kilograms, and charge in coulombs. The SI unit of magnetic field is the tesla. O 1T O .1T O .01 T O 0.001 TAn MRI main field magnet typically has a field of 1.5 T. If it had a 1000 turn coil and a length of 4 meters, what current would be required to maintain the field? Hint: This is the reason MRI magnets are usually made with superconducting wire and kept a few degrees above absolute zero to have zero electrical resistance. O Nearly 50,000 A O 1.5 A O 1200 A O 4800 A