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can you help me with General Physics: Mechanics of Solids and Fluids? 4.15 m/s2 (for both) m1 = 25.7N fi = 5.14 N T2 =
can you help me with General Physics: Mechanics of Solids and Fluids?
4.15 m/s2 (for both) m1 = 25.7N fi = 5.14 N T2 = 61.1N 12 =98.0 N f2 = 19.6N1. Two boxes are attached as shown below. When string 1 is pulled, both blocks accelerate to the right. Find the acceleration of each hloclg the tension in string 2, all normal forces, and all friction forces. Solve this by using a FED and applying Newton's Second Law to both boxes. rm = 5.13\"} kg m: = 10.0 kg T: = 9&0 N gt: 13.0\" 133': 0.300 {for both} Lecture - Friction Forces max & value before hand pushes box to the right, box initially at rest shipping Kinetic friction Zone t mart= state friction = $, " about to slip " when shipping, we have Kinetic friction, fx Is and fo are proportional to n proportional when slipping mu" coefficient of Kinetic coefficient of static Friction Friction is fkin are " about magnitudes to shop\fZFu = mam (2) - Pcase - math= 0 n P = unknowns n P z 7 Sowe system of agns for nip get P= hematma : 287N -waqtude WE LIZN 0. 150\fStep by Step Solution
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