Can you help :)?

Use the Intermediate 1Value Theorem to show that the given function has a zero in the interval [0, 3]. III) =I2+4z? f [2) IWI an the interval [I], 3]. f [0) = I Numb-er I f [3) = I Numb-er I By the Intermediate Value Theorem, there is a value c in [I], 3] such that f(c) = i}, since 0 and f(3] I Click for List v ID