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Can you please help m and answe those questions pleas. thank you so much Solve the following equations for x. (a)3e2x = 5ex + 2
Can you please help m and answe those questions pleas. thank you so much
Solve the following equations for x.
(a)3e2x = 5ex + 2 (b) 3e2x = (3a 1)ex + a, where a is a constant.
Does your answer change depending on the value of a?
2. Consider the following "proof". 3>2 3log0.5 > 2log0.5 log(0.53) > log(0.52) 0.53 > 0.52 0.125 > 0.25 Clearly this is wrong! We started with a true statement 3 > 2, performed some algebra, and arrived at an incorrect statement 0.125 > 0.25. Which step(s) are correct? Why? At which step(s) did we make a mistake? Why?
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