can you please help me with this lab , i dont know how to use this website!

https://phet.colorado.edu/sims/html/collision-lab/latest/collision-lab_en.html

V 1 V 2i V 21 P = P = P /P K = K1 = K/K m,Vli m2 V 21 0.5m,V 1iz 0.5m2V 212 (m/s (m/s (m/s (m/s (kg.m/s) (kg.m/s (J) (J) 1.00 0 3.00 0 6.00 0 Do they all have the same p, / p,? explain. Do they all have the same KE, / KE,? explain. Part (2) : Elastic Collision b) ml # m2: 1) Use the same link 2) KEEP: Elasticity 100% by dragging the blue triangle (A) to the right 3) Select: m, = 4kg and m, = 3kg 4) Position 1 (-1.00m) and position 2 (0.00m) 5) Select: v,=1.00m/s and v,=0.5m/s 6) Click on Play, then after the collision, hit pause. 7) Record the values of v, ' and v,'B) Calculate the values of p, P, , P/p, , KE, , KE, and KE /KE, and record them in the tables below. Table 2 V 21 V it V 21 P, = m,VJ+ P, = m,V 1 + P,/P, m,V21 (m/s) (m/s) (m/s (m/s) (kg.m/s) (kg.m/s) 1.00 0.50 1.50 0.75 2.00 1.00 2.50 1.25 Table 3 V 1 V 21 V it K, = (0.5m, v 7) K = K/K, + (0.5m,Va ) (0.5m, Vir ) + (m/s) (m/s) (m/s) (m/s) (0.5m, V 21 ) (J) (J) 1.00 0.50 1.50 0.75 2.00 1.00 2.50 1.25 Do they all have the same p, / p,? explain.Do they all have the same KE, / KE ? explain. Questions: 1) What is the difference between elastic and inelastic collision? 2) Show this difference using equal and unequal masses of the two balls 3) What does the quantity (KE, - KE ) represent. Conclusion:Conservation of Linear Momentum Objectives Determine the velocity of two objects after a collision and the momentum of each ball before and after the collision Collision types and kinetic energy evaluation Simulation Theory: Newton's second law is written F.. = (d p / dt), where F., is the net external force acting on the system during the collision and (p) is the net momentum of the system. This momentum is given by mass (m) times velocity (v); p = my, which is a vector quantity. If F.. = 0, then (dp/ dt) = 0, which means (p) = constant. Therefore, when two objects collide on a horizontal surface devoid of friction, the total force acting on the system during the collision is equal to zero which means that (p.) = [p.) where (p.) is the vector sum of the moment of the two objects before the collision and (p,) is the vector sum of the momentum of the two objects after collision. And for the calculation of speed: m, Vi + m, V2 = m, V1 '+ m, Vz There are two types of collisions : (1) Elastic Collision: total kinetic energy is conserved (2) Inelastic Collision: kinetic energy is not conservedProcedure: In this experiment we have two parts related to elastic collision (part 1) when m1=m2 (part 2) elastic collision when ml # m2 . Part(1); a)m1 = m2 = 2kg: 1) Open this link 2) Select Intro 3) To make the collision elastic, drag the slider of Elasticity to the right 100%. 4) Click on more data. 5) To change any value in the table click on it then type. 6) Choose the following values: a) ml = m2 = 2kg b) Position 1 (-1.00m) and position 2 (0.00m] c) Velocity of ball 1: make v = v, = 1.00 m/s d) Velocity of ball 2: make v = v, = 0 (Ball 2 is at rest) 7) This collision will take place between the blue ball (m1) and the pink ball (m2) of equal masses, with (m2) initially at rest (v,=0). The blue ball (ml) will collide with (m2) and essentially stops , then (m2) will move in the same direction that (m1) was moving before the collision. 8) Click on Play, then after the collision happens, hit pause. 9) Record the values of v, 'and v, ' 10) Calculate the values of p, , p, , p/p) , KE , KE, and KE/KE, and record them in the table below. 11) Repeat the experiment for two different values of v, (3 m/s) and (6.00 m/s) and always keep v, ZERO