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Can you solve this please? Write a function that recursively computes 2 n (i.e. 1 multiplied by 2, n times) Assume positive n (n >=
Can you solve this please?
Write a function that recursively computes 2n (i.e. 1 multiplied by 2, n times)
Assume positive n (n >= 1).
def two_pow_n(n:int) -> int:
"computes 2**n for integer n > 0"
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DB2 11 The Ultimate Database For Cloud Analytics And Mobile
Authors: John Campbell, Chris Crone, Gareth Jones, Surekha Parekh, Jay Yothers
1st Edition
