Can you solve this question with mathematical modeling in chemical engineering please

A cylindrical tank with radius 10cm and height 25cm has a drain hole at the bottom with an area of 2cm2 the keg is draining at a consant rate of 200 cm3/s. According to Toricelli's Law, water drains from a tank according to the following law: dV/dt=0.6A2gh(t) where A is the area of the hole, g is acceleration due to gravity and h(t) is the depth of the liquid. For the considered tank, how fast is the height dropping when there is 4L of water remaining in it? (g=9.81m/s2 )