Candy Bar Weights Assume that the actual weight of a certain candy bar varies according to a normal distribution with mean u = 2. 20 ounces and standard deviation o = 0. 04 ounces. Suppose you are skeptical about the manufacturer's claim that the mean weight is u = 2. 20 ounces, so you take a random sample of n = 5 candy bars and weigh them. You find a sample mean weight of 2.16 ounces. a. What does the CLT say about the distribution of sample mean weights if samples of size n = 5 are taken repeatedly? Round your answer to FOUR decimal places, if necessary. 9:54 PM 21 47OF O N 4/13/2022 Cloudy DELL PrtSer Insert Delete FO F10 F11 F12 F3 F4 F5 F6 F7 F8 F2The CLT predicts the sampling distribution of the sample mean will also be normally distributed with mean ___ and standard deviation Blank # 1 Blank # 2 47OF O Cloudy DELL F10 F11 F12 Priser F7 F8 F4 F5 F6 ESC F1 F2 F3 11 1X % &b. Is it possible to get a sample mean weight this low even if the manufacturer's claim that u = 2. 20 ounces is valid? Is it unlikely? If the manufacturer's claim that u = 2. 20 ounces is true, the probability of obtaining a random sample of five candy bars with a mean weight as small as 2.16 ounces or smaller is ( round your answer to FOUR decimal places). A 9:55 PM 4/13/2022 21 47OF Cloudy DELL F11 F12 PrtScr insert Delete FO F10 F5 F6 F7 F8 F4 F2 F3 F1 144 DII ESC X Backspac &c. Explain whether finding the sample mean weight to be 2.16 ounces provides strong evidence to doubt the manufacturer's claim that u = 2. 20 ounces. O Because the probability from part b is small, this means it is unlikely to select a random sample with a sample mean weight of 2.16 ounces or smaller, which gives us strong evidence against the underlying claim that u = 2. 20 Because the probability in part b is small, this means it is unlikely to select a random sample with a sample mean weight of 2.16 ounces or smaller, which does not give us evidence against the claim that u = 2. 20 9:55 PM 47OF O 4/13/2022 Cloudy DELL Delete FO F10 F11 F12 PriScr Insert F5 F6 F7 F8 F4 ESC F1 F2 F3 Backspace %Because the probability in part b is rather large, this gives us strong evidence against the claim that u = 2. 20, because it is likely to occur. O Because 2.16 is pretty close to 2.20, we cannot say that u = 2. 20 is an incorrect claim. O Because the probability in part b is rather large, this does not give us strong evidence against the claim that u = 2. 20, because it is likely to occur. 9:55 PM 4/13/2022 21 47 F N Cloudy DELL F12 PrtSer insert Delete F10 F11 F6 F7 F8 F9 F3 F4 F5 (F2 ESC (F1 144 X Backspace & %d. Would finding the sample mean weight to be 2.18 ounces provide strong evidence to doubt the manufacturer's claim that u = 2. 20 ounces? Explain, again referring to the sampling distribution and a probability calculation. The probability of the sample weight being as small as 2.18 ounces or smaller is _ (round to 4 decimal places) A 9:56 PM 4/13/2022 21 47 F Cloudy DELL F11 F12 PrtScr insert Delete FO F10 F5 F6 F7 F8 F3 F4 ESC F1 F2e. Explain whether finding the sample mean weight to be 2.18 ounces provides strong evidence to doubt the manufacturer's claim that Mu = 2. 20 ounces. O Because the probability in part d is small, this gives us strong evidence against the claim that u = 2. 20 Because the probability in part d is rather large, this gives us strong evidence against the claim that u = 2. 20 47 F O 9:56 PM 21 Cloudy 4/13/2022 DELL Delete F8 F9 F10 F11 F12 PrtSer Insert F7 F1 F3 F4 F5 F6 ESC F2 BackspaceBecause 2.18 is pretty close to 2.20, we cannot say that fu = 2. 20 is incorrect O Because the probability in part d is small, this does not give us strong evidence against the claim that u = 2. 20 O Because the probability in part d is rather large, this does not give us strong evidence against the claim that u = 2. 20 47OF O 9:56 PM 4/13/2022 21 Cloudy DELL Delete F11 F12 PritScr insert F4 F5 F6 F7 F8 F9 F10 B'S