Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is

S$2($g$)+$ C$($s$)=$ CS$2($g$)$

Kc $=9\mathrm{.}40$ at $900$ K

How many grams of CS$2($g$)$ can be prepared by heating $11\mathrm{.}5$ mol S$2($g$)$ with excess carbon in a $5\mathrm{.}60$ L reaction vessel held at

$900$ K until equilibrium is attained?