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Case A: Case B: For both Case A and Case B, determine the rate of entropy production. C - A+ BT +CT + D T

Case A:
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Case B:
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For both Case A and Case B, determine the rate of entropy production.
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C - A+ BT +CT + D T T in Kelvin R The constants A,B,C,D depend on the composition of the gas. In this exercise we will be considering methane, oxygen and nitrogen. For these three gases methane oxygen nitrogen 1.702 3.639 3.280 B 9.081.10 0.506-10 0.593-10 -2.164.10 0.0 0.0 D 0.0 0.227.10 0.040.10 Question 1 In Example 1.3 in Lecture Notes 1 a gas mixer, see the figure below, was analyzed in terms of entropy. Now we ask you to perform a similar analysis taking into account the temperature dependence of the heat capacities. Case A Only methane and n - 1 mol/s, n, - 2 mol/s, T, -600 K, T, - 450 K, and T=400 K. The surroundings are at T, = 330 K. The pressure of all streams is 1 bar. Stream A is methane with n - 1 mol/s, T = 600 K. Stream B is oxygen with 1, - 1 mol/s, T, - 750 K, and T=500 K. The surroundings are at T-330 K. The pressure of all streams is 1 bar. For both Case A and Case B: determine the rate at which entropy is being produced (symbol S)

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