Cesium Chloride: CsCl consists of two interpenetrating simple cubic lattices of ions. The edge length of the unit cell is a0=4.110A. . Given the radius of a cesium ion, you will determine the radius of a chlorine ion. To do so, note that 1) in an ionic structure, the edges of the ions are expected to touch and 2) exactly one Cs+ion and one Clion lie across the diagonal of the unit cell. Therefore, we can use the equations below to determine the radius of the chlorine atom. diagonal=2RCS+2RCldiagonal=(3)a0 Cesium Chloride Simple Cubic Complex Tetrahedral Crystal Type Two Interpenetrating Simple Cubic Lattices FCC BCC Coordination \# of each Cl Coordination \# of each Cs+ Assume the Atomic Radius of Cs+is 165pm. What is the Atomic Radius of Clin A ? Cell Content (Z) How many each of Cland Cs+? % Volume of Cell Occupied by Atoms: Calculated Theoretical Density (g/cm3) Reference Density (g/cm3)