Chapter 4: Discrete Random Variabl Chapter 4: Discrete Probability and the Binomial Distribution Score: 0/18 0/8 answered Question 7 30% of all college students major in STEM (Science, Technology, Engineering, and Math). If 42 college students are randomly selected, find the probability that a. Exactly 11 of them major in STEM. b. At most 13 of them major in STEM. c. At least 10 of them major in STEM. d. Between 11 and 19 (including 11 and 19) of them major in STEM. Hint: Hint Video on Finding Binomial Probabilities @ [+] Submit QuestionChapter 4: Discrete Probability and the Binomial Distribution Score: 0/18 0/8 answered Question 8 16% of all Americans live in poverty. If 49 Americans are randomly selected, find the probability that a. Exactly 7 of them live in poverty. b. At most 9 of them live in poverty. c. At least 10 of them live in poverty. d. Between 5 and 12 (including 5 and 12) of them live in poverty. Hint: Hint Video on Finding Binomial Probabilities = [+] Submit QuestionMATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 Chapter 5: Continuous Uniform Distribution Chapter 5: Uniform Distribution Score: 0/20 0/4 answered Question 1 Suppose that the weight of an newborn fawn is Uniformly distributed between 1.8 and 3.3 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. a. The mean of this distribution is b. The standard deviation is c. The probability that fawn will weigh exactly 3.1 kg is P(x = 3.1) = d. The probability that a newborn fawn will be weigh between 1.9 and 2.1 is P(1.9 2.9) = f. P ( x > 2. 1 1 x 42) = f. P(x > 24 | x 15) = f. P(x > 19 | x The average fruit fly will lay 381 eggs into rotting fruit. A biologist wants to see if the average will be greater for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 389, 375, 364, 411, 382, 391, 397, 378, 400, 390, 406, 398, 394, 391, 402, 392 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer v H1: ? Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places. ) d. The p-value = (Please show your answer to 4 decimal places. ) e. The p-value is ? v o f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly more than 381 at or = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lav in rotting fruit is more than 381 IMG_20221126_11....jpg IMG_20221126_11...jpg IMG_20221126_11....jpg IMG_20221126_11....jpgPIEDMONT TECHNICAL COLLEGE MATH1127: Introduction to Statistics (Asynchronous (100% Online)) 20337 ... Chapter 5: Hypothesis Testing with One Sample Chapter What can be concluded at the the o = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer v H1 : ? Select an answer v c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly more than 381 at a = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is more than 381. The data suggest that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is not significantly more than 381 at a = 0.05, so there is insufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is more than 381. The data suggest the population mean is not significantly more than 381 at or = 0.05, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is equal to 381. IMG_20221126_11....jpg IMG_20221126_11....jpg IMG_20221126_11....jpg IMG_20221126_11...jpg