Charge on Rod\ An electric charge of

Q=7.4C

is distributed uniformly along a rod of length

2L

, extending from

y=-13.4cm

to\

y=+13.4cm

, as shown in the diagram. A charge

q=8.95C

, and the same sign as

Q

, is placed at

(D,0)

, where\

D=77.5cm

.\ Consider the situation as described above and the following statements.\ 4a Please select all the statements that are true:\ Assuming East to be in the

x

-direction, the total force on

q

is generally in the east direction due to the\ charge on the rod.\ The charge on a segment of the rod of infinitesimal length dy is given by

dQ=((Q)/(L))dy

.\ The net force on

q

in the

x

-direction does not equal zero.\ The net force on

q

in the

y

-direction does not equal zero\ The magnitude of the force on charge q due to the small segment dy is

dF=(kq(Q)/(2)Lr^(2))dy

.\ Show feedback\ 4b Integrate to compute the total force on

q

in the

x

-direction.\ (Please answer in SI unit and multiply your answer by

10^(-11)

)

An electric charge of Q=7.4C is distributed uniformly along a rod of length 2L, extending from y=13.4cm to y=+13.4cm, as shown in the diagram. A charge q=8.95C, and the same sign as Q, is placed at (D,0), where D=77.5cm. Consider the situation as described above and the following statements. 4a Please select all the statements that are true: Assuming East to be in the x-direction, the total force on q is generally in the east direction due to the charge on the rod. The charge on a segment of the rod of infinitesimal length dy is given by dQ=(Q/L)dy. The net force on q in the x-direction does not equal zero. The net force on q in the y-direction does not equal zero The magnitude of the force on charge q due to the small segment dy is dF=(kqQ/2Lr2)dy. Show feedback 4b Integrate to compute the total force on q in the x-direction. (Please answer in SI unit and multiply your answer by 1011 ) An electric charge of Q=7.4C is distributed uniformly along a rod of length 2L, extending from y=13.4cm to y=+13.4cm, as shown in the diagram. A charge q=8.95C, and the same sign as Q, is placed at (D,0), where D=77.5cm. Consider the situation as described above and the following statements. 4a Please select all the statements that are true: Assuming East to be in the x-direction, the total force on q is generally in the east direction due to the charge on the rod. The charge on a segment of the rod of infinitesimal length dy is given by dQ=(Q/L)dy. The net force on q in the x-direction does not equal zero. The net force on q in the y-direction does not equal zero The magnitude of the force on charge q due to the small segment dy is dF=(kqQ/2Lr2)dy. Show feedback 4b Integrate to compute the total force on q in the x-direction. (Please answer in SI unit and multiply your answer by 1011 )