Cheetahs can accelerate to a speed of

20.0(m)/(s)

in

2.50s

and can continue to accelerate to reach a top speed of

27.8(m)/(s)

. Assume the acceleration is constant until the top speed is reached and is zero thereafter. Let the

+x

-direction point in the direction the cheetah runs.\ Express the cheetah's top speed

v_(top )

in miles per hour (

{

(

:m(i)/(h))

}.\

v_(top )=|~,m(i)/(h)

|\ Starting from a crouched position, how much time

t_(accel )

does it take a cheetah to reach its top speed, and what distance

d

does it travel in that time?\

t_(accel)=\ d=(O)/()

\ If a cheetah sees a rabbit

129.0m

away, how much time

t_(total )

will it take to reach the rabbit, assuming the rabbit does not move and the cheetah starts from rest?

Cheetahs can accelerate to a speed of 20.0m/s in 2.50s and can continue to accelerate to reach a top speed of 27.8m/s. Assume he acceleration is constant until the top speed is reached and is zero thereafter. Let the +x-direction point in the direction the cheetah runs. Express the cheetah's top speed vtop in miles per hour (mi/h). vtop Starting from a crouched position, how much time taccel does it take a cheetah to reach its top speed, and what distance d does it travel in that time? taccel d= If a cheetah sees a rabbit 129.0m away, how much time ttotal will it take to reach the rabbit, assuming the rabbit does not move and the cheetah starts from rest