CHEM $112$ Lab: Review of Chem $111$ Lab

Calculate the amount in grams of the solute required to make $10\mathrm{.}0mL$ of a $0\mathrm{.}15-M$ solution of each of the following:

$CO-58\mathrm{.}931$

$N-14\mathrm{.}012$

$O-16\mathrm{.}0012$

$\frac{H-1\mathrm{.}0112}{291\mathrm{.}07}$

a$.Co(N{O}_3{)}_2*6H_{2}O($s$)$

$mo{l}_{CO}(N{O}_3{)}_2\mathrm{.}6H_{2}O=\mathrm{.}15\mathrm{.}01L$ solute $=\mathrm{.}0015$mol

$\mathrm{.}0015mo{l}_{CO}(N{O}_3{)}_2\mathrm{.}6H_{2}O\frac{291\mathrm{.}07(g)}{\text{I}\text{m}\text{o}\text{l}CO(N{O}_3{)}_2\mathrm{.}6H_{2}O}=\mathrm{.}437$gCO$(N{O}_3{)}_2\mathrm{.}6H_{2}O$

b$.Ni(N{O}_3{)}_2*6H_{2}O(s)$

$Ni-58\mathrm{.}711$

$N-14\mathrm{.}012$

$0-16\mathrm{.}0012$