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Sydney Water processes wastewater from 1.4 million households at Malabar Sewage Treatment Plant. This wastewater is treated by primary sedimentation, producing primary sludge of
Sydney Water processes wastewater from 1.4 million households at Malabar Sewage Treatment Plant. This wastewater is treated by primary sedimentation, producing primary sludge of 5000 m.day-. A representative sample of primary sludge was sent to Sydney Water analytical laboratories for characterisation and the following results were produced: Specific gravity: 1.022 Moisture fraction: 0.850 Volatile fraction of total solids: 0.761 Total BMP (measured over 20 days): 220 NmL.gVS-1 The following molar masses are provided: carbon (C) = 12.0 g/mol, hydrogen (H) = 1.00 g/mol, oxygen (O) = 16.0 g/mol, nitrogen (N) = 14.0 g/mol. All gasses have a molar volume (at standard temperature and pressure) of 22.4 L.mol-. (a) Assuming the digesters operate with 85% efficiency for volatile solids degradation, determine the daily mass of methane that may be produced. [10 Marks] (b) In addition to methane, describe the other major chemical product that will be produced by this anaerobic digestion process and determine the daily mass. [5 Marks] Gravitational acceleration: g = 9.81 m.s (D-D) P BOD, =BOD (1-ek) (D-D)-(B-B)f BOD, P Alkalinity (eq/L) = [HCO;]+2 [CO]+[OH-]-[H] h dN dt == = -KN BS N = No e-kt = 2g AC = Fw = Kw (APa - A) = BOD, VsL= F/M == +c] G + Cc - Cp 2 Mw Pw = (Mw + Ms) V (m/day) = 0.35 Ms SSIPPS 3 m CH. kg COD QSi XV -p A V - = 9(Pp - Pw)d 18 E = Oc= Ms SSP 4x (COD - COD) volume of sample volume of sample plus dilution water pH = -log10[H+] COD COD(m) = 8000(B A)[Normality of FAS] V = (C-C), C APa S 9(Sp-1)d Vs 18v = = XV (Q-Qw) Xe + Qw Xr = -x100 My Mf + Sup Sfp Msl Mw Ms SslP SwP Ssp h = V(a+bV) x Q 2 V = [3.3 g(Sp-1)d] [Pr + Pc-Pp + h = f' _I (1-8) V d g U= G= 0.5 F = KAC = = R(%): Q(Si - Se) XV Cf-Cp Cf P HK QpCp A -X 100 P = (1 - Pw) = (Mw + Ms) P = EQ TS x VS BMP
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