Circle the reaction sequence that produces the following products.

a$.1\mathrm{.}2$ eq$.B{r}_2,hv$;$2\mathrm{.}2$ eq$.NaN{H}_2$;$3.H_3{O}^{+},HgS{O}_4$

b$.1\mathrm{.}2$ eq$.B{r}_2,$ hv; $2.2$ eq$.NaN{H}_2$;$3.($sia$){?}_{2}BH,$ then $H_2{O}_2,$NaOH

c$.1.B{r}_2,hv$;$2.Me{O}^{-},$MeOH;$3.O_3,$ then $M{e}_{2}S$

d$.1\mathrm{.}2$ eq$.Me{O}^{-},$MeOH;$3.Os{O}_4,$ then $NaHS{O}_4$

$2$

a$.1.B{r}_2,$ hv; $2\mathrm{.}2$ eq$.O{H}^{-},M{e}_{2}O$

b$.1.B{r}_2,hv$;$2.tBu{O}^{-},$tBuOH;$3.O_3$ then $M{e}_{2}S$

c$.1.B{r}_2,hv$;$2.tBu{O}^{-},tBuO{H}^{2}3.KMn{O}_4,$

d$.1.HBr,\frac{R}{O}OR$;$2.Me{O}^{-},$MeOH;$3.O_3$ then $M{e}_{2}S$

$3$

a$.1.$ NaOH;$2.O_3,M{e}_{2}S$

b$.1.Os{O}_4$ then $NaHS{O}_4$;$2.Hg(OAC{)}_2,H_{2}O,$ then $NaB{H}_4$

c$.1.$ NaOH;$2.H_3{O}^{+}$

d$.1.Me{O}^{-},$MeOH;$2.HBr,\frac{R}{O}OR$;$3.H_{2}O$

$4$

a$.1.$ EtOH;$2.Os{O}_4,$ then $NaHS{O}_4$

b$.1.Me{O}^{-},$MeOH;$2\mathrm{.}2$ eq$.H_3{O}^{+}$

c$.1.$ MeOH,$$;$2.KMn{O}_4,$

d$.1.$ MeOH,$$;$2.Os{O}_4$ then $NaHS{O}_4$

$5.$

a$.1.B{r}_2,hv$;$2.tBu{O}^{-},$ tBuOH; $3.HBr,\frac{R}{O}O{R}^{2}4.Et{O}^{-},E{t}_{2}O$

b$.1.B{r}_2,hv$;$2.tBu{O}^{-},$tBuOH;$3.HBr,\frac{R}{O}OR$; $4.$ EtO ${?}^{-},$EtOH

c$.1.B{r}_2,hv$;$2,tBu{O}^{-},tBuO{H}^{\text{'}}$;$3.$EtOH,$$

d$.1.B{r}_2,hv$;$2.tBu{O}^{-},$tBuOH;$3.$EtOH