Coffee: The National Coffee Association reported that 61% of U.S. adults drink coffee daily. A random sample of 250 U.S. adults is selected. Round your answers to at least four decimal places as needed. Part 1 of 6 (a) Find the mean In. The mean . is .61 Alternate Answer: The mean WA is 0.61. Part 2 of 6 (b) Find the standard deviation Of. The standard deviation On is .0308 . Alternate Answer: The standard deviation GA, is 0.0308. Part: 2 / 6 Part 3 of 6 (c) Find the probability that more than 65% of the sampled adults drink coffee daily. The probability that more than 65% of the sampled adults drink coffee daily is ].Determine whether the outcome is a Type I error, a Type II error, or a correct decision. A test is made of Ho : u = 41 versus H : u > 41, The true value of His 41, and No is not rejected. The outcome of the test is a (Choose one) Type I error X correct decision Type II errorDetermine whether the outcome is a Type I error, a Type II error, or a correct decision. A test is made of Ho : u = 20 versus 17 : u = 20. The true value of u is 25, and Mo is rejected. The outcome of the test is a (Choose one) Type I error X 5 correct decision Type II errorFertilizer: A new type of fertilizer is being tested on a plot of la nd in an orange grove, to see whe'ler it increases the amount of fruit produoed. The mean number of pounds of fruit on this plot of land with line old fertilizer was 333 pounds. Agriculture scienb'sts believe that the new.r ferb'lizer may decrease the yield. State the appropriate null and alternate hypotheses. The null hypothesis Is H.) H {Choose one] \"|:| |:|.|>= 53' {Choose one) 1' On the road again: An automobile researcher claims that the mean age of automobiles in the U.S. is 11.4 years. A test is made of Ho:u= 11.4 versus /1 : u 50. Part: 0 / 3 Part 1 of 3 If a Type I error is made, what conclusion will be drawn regarding the mean breaking strength? The conclusion will be that the mean breaking strength is (Choose one) 50. X 5 equal to not equal to less than greater than less than or greater thanA test is made of H: U= 18 versus H : u # 18. A sample of size / = 47 is drawn, and * = 20. The population standard deviation is 6 = 6. (a) Compute the value of the test statistic Z. (b) Is No rejected at the a = 0.05 level? (c) Is Ho rejected at the a = 0.01 level? Part: 0 / 3 Part 1 of 3 (a) Compute the value of the test statistic. Round the answer to at least two decimal places. 7 =Facebook: A study showed that two years ago, the mean time spent per visit to Facebook was 20.2 minutes. Assume the standard deviation is G= 10.0 minutes. Suppose that a simple random sample of 103 visits was selected this year and has a sample mean of x = 19.2 minutes. A social scientist is interested to know whether the mean time of Facebook visits has decreased. Use the o= 0.10 level of significance and the P-value method with the TI-84 calculator. (a) State the appropriate null and alternate hypotheses. (b) Compute the P-value. (c) State a conclusion. Use the o = 0.10 level of significance. Part: 0 / 4 Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho: This hypothesis test is a (Choose one) test. right-tailed X 5 left-tailed two-tailedCalibrating a scale: Making sure that the scales used by businesses in the United States are accurate is the responsibility of the National Institute for Standards and Technology (NIST) in Washington, D. C. Suppose that NIST technicians are testing a scale by using a weight known to weigh exactly 1000 grams. The standard deviation for scale reading is known to be O = 2.4. They weigh this weight on the scale 30 times and read the result each time. The 50 scale readings have a sample mean of x = 999.6 grams. The calibration point is set too low if the mean scale reading is less than 1000 grams. The technicians want to perform a hypothesis test to determine whether the calibration point is set too low. Use the a = 0.10 level of significance and the P-value method with the TI-84 calculator. Part: 0 / 4 Part 1 of 4 State the appropriate null and alternate hypotheses. H : 0 0=0 H1 This hypothesis test is a (Choose one) test. left-tailed X 5 right-tailed two-tailed\fHeavy children: Are children heavier now than they were in the past? The National Health and Nutrition Examination Survey (NHANES) taken between 1999 and 2002 reported that the mean weight of six-year-old girls in the United States was 49.3 pounds. Another NHANES survey, published in 2008, reported that a sample of 195 six-year-old girls weighed between 2003 and 2006 had an average weight of 51.2 pounds. Assume the population standard deviation is 6 = 15.4 pounds. Can you conclude that the mean weight of six-year-old girls in 2006 is different from what it was in 2002? Use the o = 0.10 level of significance and the P-value method with the TI-84 calculator. Part: 0 / 4 Part 1 of 4 State the appropriate null and alternate hypotheses. HO: 00 0=0 HE The hypothesis test is a (Choose one) test. night-tailed X left-tailed two-tailedIs there a doctor in the house? A market research firm reported the mean annual earnings of all family practitioners in the United States was $178,258. A random sample of 60 family practitioners in Los Angeles had mean earnings of x = $191,600 with a standard deviation of $42,137. Do the data provide sufficient evidence to conclude that the mean salary for family practitioners in Los Angeles is greater than the national average? Use the a = 0.10 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 State the appropriate null and alternate hypotheses. Ho 0 0=0 This hypothesis test is a (Choose one) test. left-tailed X 5 right-tailed two-tailedCollege tuition: The mean annual tuition and fees in the 2013-2014 academic year for a sample of 24 private colleges in California was $37,000 with a standard deviation of $7800, A dotplot shows that it is reasonable to assume that the population is approximately normal. Can you conclude that the mean tuition and fees for private institutions in California is greater than $35,0007 Use the a = 0.10 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 State the appropriate null and alternate hypotheses. HO: This hypothesis test is a (Choose one) test.Commuting to work: A community survey sampled 1923 people in Colorado and asked them how long it took them to commute to work each day. The sample mean one-way commute time was 25.8 minutes with a standard deviation of 13 minutes. A transportation engineer claims that the mean commute time is greater than 25 minutes. Do the data provide convincing evidence that the engineer's claim is true? Use the o = 0.10 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 State the appropriate null and alternate hypotheses. HO: 0 0=0 HE This hypothesis test is a (Choose one) test. left-tailed X right-tailed two-tailedWatching TV: In 2012, the General Social Survey asked a sample of 1336 people how much time they spent watching TV each day. The mean number of hours was 3.15 with a standard deviation of 2.72. A sociologist claims that people watch a mean of 3 hours of TV per day. Do the data provide sufficient evidence to conclude that the mean hours of TV watched per day is greater than the claim? Use the a = 0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho: 0 0=0 HE This hypothesis test is a (Choose one) test. left-tailed X 5 right-tailed two-tailedSpam: A researcher reported that 71.8% of all email sent in a recent month was spam. A system manager at a large corporation believes that the percentage at his company may be 77%. He examines a random sample of 500 emails received at an email server, and finds that 361 of the messages are spam. Can you conclude that the percentage of emails that are spam is less than 77% ? Use both a = 0.05 and o = 0.10 levels of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 State the appropriate null and alternate hypotheses. Ho: 0 0=0 HI 0#0 P This hypotheses test is a (Choose one) test. night-tailed X 5 left-tailed two-tailedKids with cell phones: A marketing manager for a cell phone company claims that the percentage of children aged 8-12 who have cell phones differs from 60%. In a survey of 824 children aged 8-12 by a national consumers group, 453 of them had cell phones. Can you conclude that the manager's claim is true? Use the o = 0.05 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho 0 0=0 HE p This hypothesis test is a (Choose one) test. X 5 night-tailed left-tailed two-tailedQuit smoking: In a survey of 444 HIV-positive smokers, 196 reported that they had used a nicotine patch to try to quit smoking Can you conclude that less than half of HIV-positive smokers have used a nicotine patch? Use the a = 0.05 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho: This hypothesis test is a (Choose one) V test,Game consoles: A poll surveyed 341 video gamers, and 72 of them said that they prefer playing games on a console, rather than a computer or hand-held device. An executive at a game console manufacturing company claims that the proportion of gamers who prefer consoles differs from 20%. Does the poll provide convincing evidence that the claim is true? Use the 0 = 0.05 level of significance and the -value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho: 0 0=0 0=0 P This hypothesis test is a (Choose one) test. X 5 right-tailed left-tailed two-tailedCuring diabetes: Vertical banded gastroplasty is a surgical procedure that reduces the volume of the stomach in order to produce weight loss. In a recent study, 82 patients with Type 2 diabetes underwent this procedure, and 59 of them experienced a recovery from diabetes. Does this study provide convincing evidence that less than 76% of those with diabetes who undergo this surgery will recover from diabetes? Use the o = 0.05 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 (a) State the appropriate null and alternate hypotheses. Ho: 0 0=0 P This hypothesis test is a (Choose one) test. X night-tailed left-tailed two-tailed