Compete with Pandas in Python:

Stupid Trick 1

Here youll create a couple of small dicts, put them in a list, and then use the list to create a Pandas DataFrame.

Step 1 - create the following three dicts.

DictA has the following key:value pairs:

a:1, b:2, c:3

DictB has these:

a:10, b:20, c:30

And, DictC has these:

a: 100, b:200, c:300

Step 2 Make ListODicts, a Python list that has the three Dicts, above, as elements.

Step 3 Use ListODicts to create a Pandas DataFrame, like pd.DataFrame(ListODicts)

Describe this DataFrame. Whats it like?

Stupid Trick 2

For this one youre going to append a couple of DataFrames

Step 1 create the following Dicts:

DictA = {a:[1,2,3,4],b:[5,6,7,8],c: [10,9,8,7]}

DictB = {a:[100,200,300,4000],c:[50,60,70,80],g:[1000,2000,3000,0000]}

Step 2 Make "FrameA," a DataFrame, using DictA, and "FrameB," a DataFrame, using DictB

Step 3 Append FrameB to FrameA so that the rows in FrameB follow the rows in FrameA. When you do this, make the index in the resulting DataFrame have unique index values for the rows.

Describe this new DataFrame. What does it look like? Is there anything about it that surprises you?