Complete Analysis of a Refrigerator Goal Solve for the performance coefficient of a refrigerator using a five-step process the includes: . Making a state table. . Making a process table. . Calculating the totals for Work, Heat, and Internal-EnergyChange. . Identifying the heat input (cold reservoir) and output (hot reservoir). . Calculating the performance coefficient of the refrigerator. Problem Shown in the figure to the right is a cyclic process undergone by a refrigerator. Your refrigerator shall use 4.0 moles of helium gas (monatomic). During the process a->b, the volume increases by a factor of 4.0. Ta = 300 K Pa = 100,000 Pa Refrigerator Cycle Solution (1) Fill in the State Table (all pressures in Pascals, all pressure Volume Temperature volumes in cubic meters, all temperatures in K). a|100000 | J | | X |300 | J b|100000 |J |997.5 |X |1500 |X cl | | | | | Work Heat dU . . v v a->b| H H | (2) Fill In the Process Table (all entries In Joules). b->c' H H ' c->a| H H | w... =:] (3) Find the Totals: Heat = :1 (4) Find the heat input (from I'cold reservoir") and Q-hot = C] J the heat output (to I*hot reservoir"): Q-cold = Z] J (5) Find the performance coefcient of the . . _ refrigerator: CoeffICIent ' :] Submit Answer Complete Analysis of a Refrigerator Goal Solve for the performance coefcient of a refrigerator using a fivestep process the includes: 1. Making a state table. 2. Making a process table. 3. Calculating the totals for Work, Heat, and InternalEnergvChange. 4. Identifying the heat input (cold reservoir) and output [hot reservoir). 5. Calculating the performance coefcient of the refrigerator. Problem Shown in the gure to the right is a cyclic process undergone by a refrigerator. Your refrigerator shall use 4.0 moles of helium gas (monatomic). During the process a>b, the volume increases by a factor of 4.0. T, = 300 K P, = 100,000 Pa Refrigerator Cycle Solution {1) Fill in the State Table (all pressures in Pascals, all Pressure Volume Temperature volumes In cubic meters, all temperatures In K). a 100000 V 0.0998 v/ w y b|100000 | |0.399 |\\_/ |1200 |\\_; c |400000 | |0.0993 | J |1200 | y Work Heat dU a |29220 | |74826 | |45606 | >13 x .7 J (2) Fill in the Process Table [all entries in Joules). [3 -55323 65323 0 \"C J J J : |0 | | 44896 | |44896 | >3 v .7 \ / w... =_x , (3) Find the Totals: Heat = V; J cw = x , (4) Find the heat input (from "cold reservoir") and Q'hOt = 400219 :7 J the heat output (to "hot reservoir"): Qcold = 74325 J _'| Elwin-ital? performance coefcient of the Coefficient = A