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Complete the following vector addition and subtraction problem using vector components. complete the table of the components of the vectors and the resultant vector components.

Complete the following vector addition and subtraction problem using vector components. complete the table of the components of the vectors and the resultant vector components. Calculate the resultant vector, the angle, and state your final solution. (Note: that the negative signs are already displayed in the table calculations).

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Complete the following vector addition and subtraction problem using vector components. Complete the table of the components of the vectors and the resultant vector components (4 marks). Calculate the resultant vector (1 mark), the angle (1 mark) and state your final solution (1 mark). (7 marks total) Note that the negative signs are already displayed and used in the table calculations. VR = V1 -V2 - V3 where m V1 = 24 , @ 53 m V2 =37 @ 2920 V3 = 23 - @ 2530 Complete the table to find the components of each vector and of the resultant vector (0.5 mark per answer, 4 marks total). (Write each answer as a decimal number rounded to four decimal places [to the nearest 0.0001]) Vector X-Components Y-Components V1 V 2 V 3 VR= V1 - V2 - V3 Determine the magnitude of Vp, include units in the second answer box. (Write you answer to the magnitude as a decimal rounded to 2 decimal places [to the nearest 0.01] - 0.5 mark. Write your units in the second answer box - 0.5 mark) IVRI = 10 Determine the reference angle and the angle in standard position. (Write your answers as decimals rounded to one decimal place [to the nearest 0. 1] - 0.5 mark each) Oret =0 State your final answer as a magnitude with units at the angle in standard position, for example VR -85.3 N @ 245 . Note the decimal rounding change at this final stage, with one decimal place for the magnitude and whole degrees for the angle. VR =@(Write you magnitude as a decimal rounded to one decimal place [to the nearest 0.1] and the angle rounded to the nearest degree - 0.5 mark each)

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