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Compute the cost assigned to ending inventory using specific identification. For specific identification, units sold include 105 units from beginning inventory, 235 units from the
Compute the cost assigned to ending inventory using specific identification. For specific identification, units sold include 105 units from beginning inventory, 235 units from the March 5 purchase, 85 units from the March 18 purchase, and 125 units from the March 25 purchase.
! Required information [The following information applies to the questions displayed below.] Warnerwoods Company uses a perpetual inventory system. It entered into the following purchases and sales transactions for March. Units Sold at Retail Units Acquired at Cost 180 units @ $52.60 per unit 265 units @ $57.60 per unit Date March 1 March 5 March 9 March 18 March 25 March 29 340 units @ $87.60 per unit Activities Beginning inventory Purchase Sales Purchase Purchase Sales Totals 125 units @ $62.60 per unit 230 units @ $64.60 per unit 210 units @ $97.60 per unit 550 units 800 units 3. Compute the cost assigned to ending inventory using (a) FIFO, (b) LIFO, (C) weighted average, and (d) specific identification. For specific identification, units sold include 105 units from beginning inventory, 235 units from the March 5 purchase, 85 units from the March 18 purchase, and 125 units from the March 25 purchase. Complete this question by entering your answers in the tabs below. Perpetual FIFO Perpetual LIFO Weighted Average Specific Id Compute the cost assigned to ending inventory using specific identification. For specific identification, units sold include 105 units from beginning inventory, 235 units from the March purchase, and 125 units from the March 25 purchase. Specific Identification: Goods Purchased Cost of Goods Sold Date Cost per # of units Goods Puchased # of units sold Cost of Goods Sold unit $ 52.60 180 at = at = $ Cost per unit $ 52.60 $ 57.60 $ 62.60 March 1 March 5 0.00 Inventory Balance Cost per # of units unit Inventory Balance at $ 52.60 = $ 0.00 at $ 57.60 - at $ 62.60 = 0.00 at $ 64.60 = 265 at $ 57.60 = $ 9,468 15,264 7,825 $ 14,858 at = 125 at $ 62.60 = at = 0.00 March 18 March 25 230 at $ 64.60 = at $ 64.60 = Totals $ 0.00 $ 0.00Step by Step Solution
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