Compute the value of the improper integral. $($If the integral diverges to $,$ type oo; if the integral diverges

to $-,$ type $-$oo; and if the integral diverges for some other reason, type DNE.$)$

${\displaystyle \underset{2}{\overset{}{}}}\frac{dx}{(9x+6{)}^5}=$

Use your answer to help determine whether the series ${\displaystyle \underset{n=2}{\overset{}{}}}\frac{1}{(9n+6{)}^5}$ converges or diverges. Enter $C$ if the

series is convergent, D if the series is divergent, or $?$ if the In tegral Test does not apply: