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Computer Organization and Architecture. Above is also mentioned with example how to solve. NEED CLEAR ANSWER. Apply the basics that we learnt through practical-sized 32-bit

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Computer Organization and Architecture. Above is also mentioned with example how to solve. NEED CLEAR ANSWER.

Apply the basics that we learnt through practical-sized 32-bit IEEE standard format for floating-point numbers in the class. In this question, we will use a shortened format that retains all the pertinent concepts but is manageable for working through numerical exercises. Consider an X-bit floating point number format where X and n is calculated as under, X= Number of bits for floating-point number n = Number of bits for exponent field Calculation for X Let's say your registration number is FA18-BCE-abc Temp= a +b+c If temp has the answer as mn (multiple digits) Then X=m+1+8 If temp has the answer as m (single digit) Then X=m+8 You may check the following examples for reference. 1. Registration Nuinber: FA18-BCE-005 Temp=0+0+5=5 X=Temp+8=8+5=13 2. Registration Number: FA18-BCE-184 Temp = 1+8+4= 13 (2 digits) add again Temp = 1+ 3 = 4 X=Temp +8=4+8=12 Bit Calculation If your resultant X is Even then Bits for exponents = 1/2 If your resultant X is Odd then Bits for exponents = (1-192 a) Represent the numbers -0.012 and 125 in this format (10) b) Perform addition operation on the operands A & B and represent the number as a X bit floating point number (10) A=010011101101000...0 B=1000111101010000...0

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