Computer Organization

Part I:

For the Debugger interface shown in Fig 1, answer the following questions:

What are the contents of register BL (in hex format)? Ans:

What is the byte stored at memory address 012B (hex format)? Ans:

What is unsigned decimal number stored in the byte at memory address 012B? Ans:

What is the length of the instruction ADD BX, 0002 in bytes? Ans:

What are the contents of register BP (in hex format)? Ans:

What is the word stored at memory address 012D (hex format)? Ans:

What is unsigned decimal number stored in the word at memory address 012D? Ans:

What is the machine code for instruction MOV AX,[BX] ? Ans:

Part II:

For the Register window contents shown in Fig 1, what are the contents of register AL (in hex format) after the execution of instruction below? add al, cl

Ans:

For the Register and Memory window contents shown in Fig 1, what are the contents of register AX (in hex format) after the execution of instruction below?

mov ax, [bx + 4] Ans:

For the Register and Memory window contents shown in Fig 1, what is the unsigned decimal number stored in register AX after the execution of instructions below?

mov ax, 10

add ax, [bx]

Ans:

What is the unsigned decimal number stored in register AL after the execution of instructions below?

mov al, [num + 1]

add al, [num + 3]

num: db 10, 20, 30, 40, 50

Ans:

What is the unsigned decimal number stored in register AX after the execution of instructions below?

mov ax, [data]

add ax, [data + 4]

data: dw 10, 20, 30, 40, 50

Ans:

What is the unsigned decimal number stored in register AX after the execution of instructions below?

mov bx, data

mov si, 2

mov ax, [bx + si]

add ax, [bx + si + 4]

data: dw 10, 20, 30, 40, 50

Ans:

_ 8. DOSBox 0.74, Cpu speed: 3000 cycles, Frameskip 0, Program: AFD AX 4000 SI 0000 CS 1975 IP 011F Stack +0 0000 Flags 7204 BX 0123 DI 0000 DS 19F5 +2 20CD CX 002D BP 012B ES 1975 HS 19F5 +4 9FFF OF DF IF SF ZF AF PF CF DX 0000 SP FFFE SS 1975 FS 19F5 +6 EAOO 0 0 1 0 0 0 1 0 CMD > 010B 83C302 010E 83C502 0111 8B07 0113 894600 0116 8B4702 0119 894602 011C B8004C 011F CD21 0121 64 ADD ADD MOV MOV MOV MOV MOV INT DB BX,0002 BP,0002 AX,[BX] [BP+001,AX AX,[BX+02] [BP+02],AX AX, 4000 21 64 1 0 1 2 3 4 5 6 7 DS:0100 BB 21 01 BD 27 01 8B 07 DS:0108 89 46 00 83 C3 O2 83 C5 DS:0110 02 8B 07 89 46 00 8B 47 DS:0118 02 89 46 O2 B8 00 4C CD DS:0120 21 64 00 08 00 2C 01 64 DS:0128 00 00 00 08 00 2C 01 7E DS:0130 8C E8 78 BD DE F9 36 ZA DS:0138 66 2C 1E DC D4 1F D7 32 DS:0140 8D A8 3A 6A 48 94 DA 1C DS:0148 79 74 99 ZA ED 06 51 F2 2 DS:0100 DS:0110 DS:0120 DS:0130 DS:0140 0 1 2 3 4 5 6 7 BB 21 01 BD 27 01 8B 07 O2 8B 07 89 46 00 8B 47 21 64 00 08 00 2C 01 64 8C E8 78 BD DE F9 36 2A 8D A8 3A 6A 48 94 DA 1C 8 9 A B C D E F 89 46 00 83 C3 02 83 C5 02 89 46 O2 B8 00 4C CD 00 00 00 08 00 2C 01 7E 66 2C 1E DC D4 1F D7 32 79 74 99 2A ED 06 51 F2 L. 1.". ef.af.at ..eF. .eF.j.L 10.4.,.d iox!|-6* f,.,.#2 il:jls. ytxe.Q 1 Step 2ProcStep 3Retrieve 4 Help ON SBRK Menu 6 7 up 8 dn 9 le 10 ri