computer science major, data sci and applied Mach learn Section. please need help, answer step 4, 5, 6, and 7. already have step 1, 2, and 3 but need help with the rest

Originating from the American TV program, "Let's Make a Deal," the Monty Hall problem gives a contestant a chance to win a car. There are three doors and behind one is a brand new car. The other two doors are hiding goats. The contestant chooses a door: the first, second, or third. Then the host Monty Hall opens up one of the other two doors remaining to reveal a goat. There are now two unopened doors, the one the contestant originally chose and the other un-opened door. Behind one is a goat and behind the other is a car. The contestant is given the option to stay with their originally-chosen door or to switch to the other door. Which should they do? Or does it not matter? Create a python simulation to answer this question. You may use the following seven steps as a guide, or you may develop your own. What matters is that you - Create a computer simulation that follows the Monty Hall problem, - Generate a Monte Carlo probability of winning a car for each of the choices of staying and switching doors, and - Provide a recommendation of whether the contestant should stay or switch doors. Step 1. (5 Points) Create a numpy array doors with the three possibiliites: goat one, goat two, and car. The contestant randomly chooses a door; simulate this by randomly choosing one of these three using np. random.choice () and calling it original_choice. [ ] ... Step 2. (5 Points) Now the host reveals a goat behind one of the two un-chosen doors. If the contestant had chosen a door with a goat behind it, then there is only one other door with a goat and that one will be opened by the host. If the contestant had chosen the door with the car behind it, then both un-chosen doors contain goats and the host will randomly decide which one to open. Simulate this. Call the goat-door the host reveals revealed_door . Hint: Use if statements. Step 3. (5 Points) Copy your code from Step 2 and modify it to assign what is left behind the third (un-chosen and un-revealed) door within the if statements, so as to be more computationally concise. Call this door the other_door. Step 4. (10 Points) Create a variable named choice that will simulate whether the contestant decides to stay with their original door or switch. choice will be either the string "stay" or "switch". Create a variable final_choice, which will be equal to original_choice if the contestant chose to stay, and equal to other_door if the contestant chose to switch. Step 5. (15 Points) Now you have everything you need to create a function monty_hall which will run one simulation of the game. The function will take one parameter, choice, and will return the final_choice of the contestant. Test your new function by calling it with both 'stay' and 'switch' and see if the contestant wins a goat or a car. 'car' Step 6. (20 Points) Find the probability of winning a car if the contestant chooses to stay with their original choice. Do this by running monty_hall('stay') 10,000 times, each time appending what the contestant won to a numpy array called winnings . Then count how many times the contestant won the car, and divide by how many trials there were, to arrive at the final odds of winning a car when choosing to stick with the original door. Call this winning_chance. Hint: Use a for loop. Step 7. (20 Points) Now find the probability of winning a car if the contestant chooses to switch doors (do the same thing as Step 6 but for the contestant choosing the other door)