Consider a $1$:$1$ electrolyte consisting of a cation, $x^{+},$ and an anion, $Y^{-}$in the moving boundary apparatus. If the concentration of the electrolyte is $0\mathrm{.}061M,$the total current is $1\mathrm{.}74mA,$ the transference number of $x^{+}$is $0\mathrm{.}772,$ the mobility

of $x^{+}$is ${37\mathrm{.}6610}^{-4}*c{m}^2*V^{-1}*s^{-1},$ and the cross$-$sectional area of the tube is $0\mathrm{.}074c{m}^2,$ then what is the electric field in the solution?

Report your answer with $3$ decimal places, in units of $\frac{V}{c}m.$