Consider a binary mixture of 10 mole\% chloroform (1) in acetone (2) at 333K and 10 bar. The second virial coefficients for this system are reported to be B11=910,B22=1330, and B12=2005cm3/mol. Determine v1,V1, and vmix. SOLUTION Applying the equations for the pure species and partial molar volumes above, we get: v1=PRT+B11=1860[cm3/mol] and, V1=PRT+(x12+2x1x2)B11+x22B12x22B22=991[cm3/mol] where we represent the liquid mole fractions by xi instead of yi. Using Equation (6.27) gives vmix=x1x2(2B12B11B22)=372[cm3/mol] (E6.12C)