Consider a miniature binary computer whose floating-point words consist of4binary (i.e., base-2)digits for the mantissa and3binary digits for the exponent (plus sign bits).

x= .1101_2 *2^0, y= .1100_2 *2^0 z=fl(x+(y/16)) show work and it a decimal point if you cant see and also it y/16

it why is this exact and not rounded when normalized