Consider a system with two springs as shown. Using the principle of minimum potential energy and following the procedure shown in the class, formulate Ku = F. Here u = (ux, uy). Express the components of K and F. The extensions of springs are SA and SB, respectively, and assume = u and = (u +u)/2. Then, for k = 100 N/m, kB = 200 N/m and P = 10 N, solve for ux and uy. 45 KA Ux