Consider a TCP session where the congestion window is always oscillating between Wmin

$-$

$5$

$0$

$$packets and Wmax

$-$

$1$

$0$

$0$

$$packets using additive increase. The session suffers from packet loss and the packet loss rate is denoted L

$.$

$$assume rtt is equal to

$2$

$$ms

$.$

$$calcuate the following quantities. The loss rate L is equal to

$1$

$$packet in every

$\_$

$\_$

$\_$

$\_$

$\_$

$\_$

packets.

if L becomes

$1$

$1$

$$in every

$1$

$0$

$.$

$0$

$0$

$0$

$$packets$,$ then Wmax becomes

$\_$

$\_$

$\_$

packets. For this new Wmax, the TCP session throughput is about

$\_$

$\_$

$\_$

$\_$

$\_$

$\_$

packets

$/$

ms

$.$Use these known results:

The sum: S $-$ w $+($w$+1)+($w$+2)+.+2$w $=3$w$($w$+1)/2.$

For large w$.3$w$0$w$+1$V$2-3$w$212.$

TCP throughput is approx. Wavg$/$RTT$.$